At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point `("-"4,"-"3)` . Find the equation of the curve given that it passes through `(2,"-"1)` .

Explanation

To solve the given problem, we will follow these steps:

### Step 1: Understand the relationship between the slopes
The slope of the tangent to the curve at any point \((x, y)\) is given by \(\frac{dy}{dx}\). According to the problem, this slope is twice the slope of the line segment joining the point \((x, y)\) to the point \((-4, -3)\).

### Step 2: Calculate the slope of the line segment
The slope of the line segment joining the points \((x, y)\) and \((-4, -3)\) can be calculated using the formula:
\[
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