Experiments show that radium disintegrates at a rate proportional to the amount of radium present at the moment. It's half life is `1590` years. What percentage will disappear in one year? [Use `e^(-log2/1590)=0. 9996`]

Experiments show that radius disintegrates at a rate proportional to the amount of radium present at the moment. Its half life is 1590 years. What percentage will disappear in one year? [Use e^(-log2/1590)=0. 9996 ]

If is given that radium decomposes at a rate proportional to the amount present. If p % of th original amount of radium disappears in l years, what percentageof it will remain after 2l years?

A radioactive substance disintegrates at as rate proportional to the amount of substance present. If 50% f the given amount disintegrates in 1600 years. What percentage of the substance disintegrates i 10 years ? (-log2)/(160)T a k ee=0. 9957

Radium decomposes at a rate proportional to the quantity of radium present. It is found that in 25 years, approximately 1.1% of a certain quantity of radium has decomposed. Determine approximately how long it will take for one-half of the original amount of radium to decompose? [Given (log)_e 0.989=0. 01106a n d(log)_e2=0. 6931 ]

1 mg redium has 2.68xx10^18 atoms. Its half life is 1620 years. How many radium atoms will disintegrate from 1 mg of pure radium in 3240 years ?

Radium has atomic weight 226 and half life of 1600 years. The number of disintegrations produced per second from one gram is

Radium Ra^236 has a half-life of 1590 years. How much of the original amount of Ra^236 would remain after 6360 year ?

The rate of growth of a population is proportional to the number present. if the population of a city doubled in the past 25 years, and the present population is 100000, when will the city have a population of 500000? [Given, log_e 5 = 1.609 , log_e 2 = 0.6931 . ]

The rate at which radioactive substances decay is known to be proportional to the number of such nuclei that are present in a given sample. In a certain sample 10% of the original number of radioactive nuclei have undergone disintegration in a period of 100 years. Find what percentage of the original radioactive nuclei will remain after 1000 years.

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Half life of .^(60)Co is 5.3 years, the time taken for 99.9% decay will be