The image of the point (1, 3, 4) in the plane `2x-y+z+3=0` is `(3,\ 5,\ 2)` b. `(-3,5,\ 2)` c.`(3,\ 5,\ -2)` d. `(3,\ -5,\ 2)`

Find the image of the point P (3, 5, 7) in the plane 2x + y + z=0 .

Find the reflection of the point (1,\ 2,\ -1) in the plane 3x-5y+4z=5.

Find the image of the point (2,-3,4) with respect to the plane 4x+2y-4z+3=0

Find the image of the point (0,2,3) in the line (x+3)/(5)= (y-1)/(2) = (z+4)/(3) .

Find the image of the line (x-1)/3=(y-2)/4=(z-3)/5 on the plane x-2y+z+2=0 .

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

The equation of the plane through the point (1,2,3) and parallel to the plane x+2y+5z=0 is

Find the distance of the point (2, 3, 4) from the plane 3x + 2y + 2z + 5= 0 measured parallel to the line (x+3)/3=(y-2)/6=z/2 .

The distance of the point (1, 2, 3) from the plane x+y-z=5 measured along the straight line x=y=z is 5sqrt(3) (2) 10sqrt(3) (3) 3sqrt(10) 3sqrt(5) (5) 2sqrt(5)