Home
Class 12
MATHS
The probability that in a year of 22nd c...

The probability that in a year of `22nd` centurychosen at random, there will be 53 Sundays is

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • MEAN VALUE THEOREMS

    RD SHARMA ENGLISH|Exercise All Questions|134 Videos
  • RELATIONS

    RD SHARMA ENGLISH|Exercise All Questions|197 Videos

Similar Questions

Explore conceptually related problems

The probability that an year chosen at random has 53 Sundays is :

The probability that a non-leap year selected at random will have 53 Tuesday or Wednesdays

Find the probability that a leap year, selected at random, will contain 53 Sundays.

Find the probability that a leap year, selected at random, will contain 53 Sundays.

The probability that a leap year selected at random will contain either 53 Thursday or 53 Friday is

The probability that a leap year selected ar random contains either 53 sundays or 53 mondays, is

Find the probability that the leap year selected at random will contain of exactly 52 Wednesdays.

What is the probability that a leap year has 52 Mondays?

The probability that a non-leap your selected at random will contain 53 Sunday is

The probability that in a family of 5 members,exactly two members have birthday on sunday is:-

RD SHARMA ENGLISH-PROBABILITY-All Questions
  1. A bag X contains 2 white and 3 black balls and another bag Y contains ...

    Text Solution

    |

  2. Two persons A and B take turns in throwing a pair of dice. The first ...

    Text Solution

    |

  3. The probability that in a year of 22nd centurychosen at random, there ...

    Text Solution

    |

  4. From a set of 100 cards numbered 1 to 100, one card is drawn at random...

    Text Solution

    |

  5. If A and B are two events such that P(A)=4/5, a n d\ P(AnnB)=7/(10), t...

    Text Solution

    |

  6. If A and B are two events associated to a random experiment such that ...

    Text Solution

    |

  7. If P(A)=3//10 , P(B=2//5) and P(AuuB)=3//5 then P(A//B)+P(B//A) equals...

    Text Solution

    |

  8. Let P(A)=7/(13), P(B)=9/(13) and P(AnnB)=4/(13) . Then P( A //B)= 5/...

    Text Solution

    |

  9. If P(A)=2/5,P(B)=3/10andP(AcapB)=1/5 then P(A'/B')cdotP(B'/A') is equa...

    Text Solution

    |

  10. If A and B are two events such that P(A)=1/2, P(B)=1/3,\ P(A//B)=1/4, ...

    Text Solution

    |

  11. Let A and B be two events such tat P(A)=3/8,\ P(B)=5/8a n d\ P(AuuB)=3...

    Text Solution

    |

  12. If P(B)=3/5, p(A//B)=1/2 and P(AuuB)=4/5, t h e n\ P(B//A)= 1/5 b. 3/...

    Text Solution

    |

  13. If A and B are two events such that P(A)=0. 4 ,\ P(B)=03\ a n d\ P(Auu...

    Text Solution

    |

  14. If A and B are two events such that A!=varphi,\ B=varphi, then a.P(A//...

    Text Solution

    |

  15. If the events A and B are independent then P(AnnB) is equal to :: a.P...

    Text Solution

    |

  16. If A and B are two independent events with P(A)=3/5a n d\ P(B)=4/9, t ...

    Text Solution

    |

  17. If A and B are two independent events such that P(A)=0. 3 ,\ P(AuuB)=0...

    Text Solution

    |

  18. A flash light has 8 batteries out of which 3 are dead. If two batterie...

    Text Solution

    |

  19. A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random ...

    Text Solution

    |

  20. A bag containing 5 red and 3 blue balls. If 3 balls are drawn at rando...

    Text Solution

    |