The score of Ishita in Mathematics is `25` more than the two third of her score in Science. If she scored `x` marks in Science, determine her score in Mathematics.

Options

A. `(2)/(3)x +25`
B. `(3)/(2)x +25`
C. `(2)/(3x) +25`
D. `(2)/(3)x -25`

Answer

To determine Ishita's score in Mathematics based on her score in Science, we can follow these steps:

1. **Identify Ishita's score in Science**: Let Ishita's score in Science be represented by the variable \( x \).

2. **Calculate two-thirds of her Science score**: To find two-thirds of her score in Science, we multiply her score \( x \) by \( \frac{2}{3} \):
\[ \text{Two-thirds of Science score} = \frac{2}{3} \times x = \frac{2x}{3} \]

3. **Add 25 to the two-thirds of her Science score**: According to the problem, Ishita's score in Mathematics is 25 more than two-thirds of her Science score. Therefore, we can express her score in Mathematics as:
\[ \text{Score in Mathematics} = \frac{2x}{3} + 25 \]

4. **Combine the terms**: To express this in a single fraction, we can convert 25 into a fraction with a denominator of 3:
\[ 25 = \frac{25 \times 3}{3} = \frac{75}{3} \]
Now we can add the two fractions:
\[ \text{Score in Mathematics} = \frac{2x}{3} + \frac{75}{3} = \frac{2x + 75}{3} \]

5. **Final expression**: Thus, Ishita's score in Mathematics can be expressed as:
\[ \text{Score in Mathematics} = \frac{2x + 75}{3} \]

### Summary
Ishita's score in Mathematics is given by the formula:
\[ \text{Score in Mathematics} = \frac{2x + 75}{3} \]