The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. Find the area of the triangle.

Explanation

Let the length of the two equal sides be x.

Perimeter of triangle=`32=2x+12`

=>`x=10`

Area of triangle=`sqrt(s(s-a)(s-b)(s-c))` where s is the semiperimeter of triangle

`s=32/2=16`

`sqrt(16xx6xx6xx4)=4 xx 6xx 2=48(cm)^2`