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The amount of extension in an elastic sp...

The amount of extension in an elastic spring varies directly as the weight hung on it. If a weight of 150 gm produces an extension of 2.9 cm, then what weight would produce an extension of 17.4 cm?

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The amount of extension in an elastic string varies directly as the weight hung on it. If a weight of 150 gm produces an extension of 2.9 cm, what would produce an extension of 17.4 cm?

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When a tensile or compressive load 'P' is applied to rod or cable, its length changes. The change length x which, for an elastic material is proportional to the force Hook' law). P alpha x or P = kx The above equation is similar to the equation of spring. For a rod of length L , area A and young modulue Y . the extension x can be expressed as. x = (PL)/(AY) or P = (AY)/(x) , hence K = (AY)/(L) Thus rod or cables attached to lift can be treated as springs. The energy stored in rod is called strain energy & equal to (1)/(2)Px . The loads placed or dropped on the floor of lift cause stresses in the cable and can be evaluted by spring analogy. If the cable of lift cause stresses and load is placed dropped, then maximum extension in cable can be calculated by energy conservation. In above problem if mass of 10 kg falls on the massless collar attached to rod from the height of 99cm then maximum extension in the rod is equal (rod of length 4m, area 4cm^(2) and young modules 2 xx 10^(10)N//m^(2) g = 10m//sec^(2) )-

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When a load of 10 kg is hung from the wire, then extension of 2m is produced. Then work done by restoring force is

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A wire is suspended vertically from a rigid support. When loaded with a steel weight in air, the wire extends by 16cm . When the weight is completely immersed in Water, the extension is reduced to 14 cm . The relative density of the material of the weight is

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