The mercury manometer consists if two unequal arms of equal cross section `1 cm^(2) and lenghths 100cm and 50cm. The two open ends are sealed with air in the tube at a pressure of 80cm of mercurey. Some amount of mercury is now introduced in the manometer through the stopcock connected to it. If mercury rises in the shorter tube to a lenght 10cm in steady state, find the length of the mercury column risen in the longer tube.

Explanation

To solve the problem step by step, we will analyze the mercury manometer and apply the principles of pressure and volume in the context of the Kinetic Theory of Gases.

### Step-by-Step Solution:

1. **Understanding the Setup**:
- We have a mercury manometer with two arms: one shorter (50 cm) and one longer (100 cm).
- The cross-sectional area of both arms is equal (1 cm²).
- Initially, the pressure of the air sealed in the manometer is 80 cm of mercury.
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