A vessel containing water is put in a dry sealed room of volume `76m^(3)`at a temperture of `15^(@)C`. The saturation vapour pressure of water at `15^(@)C`. is 15mm of mercury. How much water will evaporate before the water is in equilibrium with the vapour?

Explanation

To solve the problem step by step, we will follow the reasoning outlined in the video transcript while providing a clear explanation for each step.

### Step 1: Understand the Given Information
We have a sealed room of volume \( V = 76 \, \text{m}^3 \) at a temperature of \( T = 15^\circ C \). The saturation vapor pressure of water at this temperature is given as \( P_{sat} = 15 \, \text{mm of Hg} \).

### Step 2: Convert Saturation Vapor Pressure to Pascals
To use the saturation vapor pressure in calculations, we need to convert it from mm of mercury to Pascals. The conversion can be done using the formula:

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