A gas cylinder has walls that can bear a maximum pressure of `1.0xx10^(6)`Pa. It contains a gas at `8.0xx10^(5)`Pa and 300K. The cylinder is steadily heated. Neglecting any change in the volume calculate the temperature at which the cylinder will break.

Explanation

To solve the problem, we will use the relationship between pressure and temperature for an ideal gas, given that the volume remains constant. The relevant equation is derived from the ideal gas law, which states that for a constant volume, the ratio of pressure to temperature is constant.

### Step-by-Step Solution:

1. **Identify Given Values**:
- Maximum pressure the cylinder can withstand, \( P_2 = 1.0 \times 10^6 \, \text{Pa} \)
- Initial pressure inside the cylinder, \( P_1 = 8.0 \times 10^5 \, \text{Pa} \)
- Initial temperature, \( T_1 = 300 \, \text{K} \)
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