The temperature and pressure at Simla are `15.0^(@)C` and 72.0cm of mercury and at Kalka these are `35.0^(@)C` and 76.0 cm of mercury. Find the ratio of air density at Kalka to the air density at Simla.

Explanation

To find the ratio of air density at Kalka to the air density at Simla, we can use the ideal gas law and the formula for density derived from it. Here’s a step-by-step solution:

### Step 1: Convert Temperatures to Kelvin
- The temperature at Simla is given as \(15.0^\circ C\).
\[ T_{Simla} = 15 + 273 = 288 \, K \]
- The temperature at Kalka is given as \(35.0^\circ C\).
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