two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at `0(@)C` at a pressure of 76cm of mercury. One of the bulbs is then placed in melting ice and the other is placed in a water bath maintained at `62^(@)C`.What is the new value of the pressure inside the bulbs? The volume of the connecting tube is neigligible.

Explanation

To solve the problem, we will use the ideal gas law and the concept of moles of gas in the two bulbs. We will follow these steps:

### Step 1: Write down the given values.
- Initial pressure, \( P_1 = 76 \, \text{cm of Hg} \)
- Initial temperature, \( T_1 = 0^\circ C = 273 \, \text{K} \)
- Temperature of the first bulb (in melting ice), \( T_2 = 0^\circ C = 273 \, \text{K} \)
- Temperature of the second bulb (in water bath), \( T_3 = 62^\circ C = 335 \, \text{K} \)

...