Pure water vapour is trapped in a vessel of volume `10cm^(3)`. The relative humidity is 40%. The vapour is compressed slowly and isothermally.find the volume of the vapour at which it will start condendsing.

Explanation

To solve the problem of determining the volume of water vapor at which it will start condensing, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Given Information:**
- Volume of the vessel, \( V = 10 \, \text{cm}^3 = 10 \times 10^{-6} \, \text{m}^3 \)
- Relative humidity, \( RH = 40\% = 0.4 \)

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