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The kinetic energy K of a rotating body ...

The kinetic energy K of a rotating body depends on its moment of inertia I and its angular speed `omega`. Assuming the relation to be `K=kI^(alpha) omega^b` where k is a dimensionless constatnt, find a and b. Moment of inertia of a spere about its diameter is `2/5Mr^2`.

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To solve the problem, we need to find the values of \( a \) and \( b \) in the equation \( K = k I^a \omega^b \), where \( K \) is the kinetic energy, \( I \) is the moment of inertia, and \( \omega \) is the angular speed. We will use dimensional analysis to achieve this. ### Step-by-Step Solution: 1. **Identify the dimensions of kinetic energy \( K \)**: The dimension of kinetic energy is given by: \[ [K] = [\text{Energy}] = [\text{Mass}] \times [\text{Length}]^2 \times [\text{Time}]^{-2} = M^1 L^2 T^{-2} \] 2. **Identify the dimensions of moment of inertia \( I \)**: The moment of inertia for a sphere about its diameter is given as: \[ I = \frac{2}{5} M r^2 \] Thus, the dimension of moment of inertia is: \[ [I] = [\text{Mass}] \times [\text{Length}]^2 = M^1 L^2 \] 3. **Identify the dimensions of angular speed \( \omega \)**: Angular speed \( \omega \) has the dimension of: \[ [\omega] = [\text{Time}]^{-1} = T^{-1} \] 4. **Write the dimensions of the right-hand side of the equation**: The right-hand side of the equation is \( K = k I^a \omega^b \). Since \( k \) is dimensionless, we can ignore its dimensions. Therefore, the dimensions can be expressed as: \[ [K] = [I]^a \times [\omega]^b = (M^1 L^2)^a \times (T^{-1})^b = M^a L^{2a} T^{-b} \] 5. **Set up the dimensional equation**: Now we equate the dimensions from both sides: \[ M^1 L^2 T^{-2} = M^a L^{2a} T^{-b} \] 6. **Compare the powers of each dimension**: - For mass \( M \): \[ a = 1 \] - For length \( L \): \[ 2a = 2 \implies a = 1 \quad (\text{This confirms our previous result}) \] - For time \( T \): \[ -b = -2 \implies b = 2 \] 7. **Final values**: From the comparisons, we find: \[ a = 1, \quad b = 2 \] ### Conclusion: The values of \( a \) and \( b \) are: \[ \boxed{a = 1, \quad b = 2} \]

To solve the problem, we need to find the values of \( a \) and \( b \) in the equation \( K = k I^a \omega^b \), where \( K \) is the kinetic energy, \( I \) is the moment of inertia, and \( \omega \) is the angular speed. We will use dimensional analysis to achieve this. ### Step-by-Step Solution: 1. **Identify the dimensions of kinetic energy \( K \)**: The dimension of kinetic energy is given by: \[ [K] = [\text{Energy}] = [\text{Mass}] \times [\text{Length}]^2 \times [\text{Time}]^{-2} = M^1 L^2 T^{-2} ...
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