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The coefficient of static friction betwe...

The coefficient of static friction between a block of mass m and an incline is `mu_s=0.3`, a. What can be the maximum angle `theta` of the incline with the horizontal so that the block does not slip on the plane? b. If the incline makes an angle `theta/2` with the horizontal, find the frictional force on the block.

Text Solution

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To solve the problem, we will break it down into two parts as stated in the question. ### Part a: Finding the Maximum Angle \( \theta \) 1. **Identify the Forces Acting on the Block**: - The weight of the block \( mg \) acts vertically downward. - The normal force \( N \) acts perpendicular to the incline. - The frictional force \( f \) acts parallel to the incline, opposing the motion. ...
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A block of mass 2 kg rests on a rough inclined plane making an angle of 30° with the horizontal. If mu_(S)= 0.6 , what is the frictional force on the block ?

The coefficient of static friction between the two blocks shown in figure is mu and the table is smooth. What maximum horizontal forced F can be applied to he block of mass M so that the block move together?

Knowledge Check

  • The coefficient of static friction between the two blocks shown in figure is mu and the table is smooth. What maximum horizontal forced F can be applied to he block of mass M so that the block move together?

    A
    0.15mg
    B
    0.05mg
    C
    0.1mg
    D
    0.45mg

  • A block of mass m is at rest on an inclined plane. The coefficient of static friction is mu . The maximum angle of incline before the block begins to slide down is :

    A
    `"tan"^(-1)(mu//m)`
    B
    `"tan"^(-1)(mu)`
    C
    `"tan"^(-1)(mu//2)`
    D
    `"cos"^(-1)(mu)`

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    The coefficient of friction between the block A of mass m and the triangular wedge B of mass M is mu . There in no friction between the wedge and the plane if the system (block A+ wedge B) is released so that there is no stiding between A and B find the inclination theta

    A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. If mu=(3)/(4) then what will be frictional force (shear force) acting between the block and inclined plane when theta=30^@ :

    A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. For what value of theta will the block slide on the inclined plane:

    A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. If the entire system, were accelerated upward with acceleration a the angle of repose, would:

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