A body of mass 2 kg is lyign on rough inclined plane of inclination `30^0`. Find the mgnitude of the force parallel to the incline needed to make tkheblock move a. up the incline b. down the incline. Coefficient of static friction =0.2

Explanation

To solve the problem, we need to find the forces acting on a block of mass 2 kg lying on a rough inclined plane with an angle of inclination of \(30^\circ\) and a coefficient of static friction of 0.2. We will calculate the force required to move the block both up and down the incline.

### Step-by-Step Solution:

1. **Identify the Forces Acting on the Block:**
- The weight of the block (\(W\)) acts vertically downward and is given by:
\[
W = mg = 2 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 19.6 \, \text{N}
...