A fighter plane is pulling out for a dive t a speed of 900 km/hr. Assuming its path to be a vertical circle of radius 2000 m and its mass to be 16000 kg, find the force exerted by tehair on it at the lowest point. Take `g=9.8m/s^2`.

Explanation

To solve the problem, we need to find the total force exerted by the air on the fighter plane at the lowest point of its vertical circular path. The forces acting on the plane at this point include its weight and the force exerted by the air (lift).

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Speed of the plane, \( v = 900 \, \text{km/hr} \)
- Radius of the circular path, \( r = 2000 \, \text{m} \)
- Mass of the plane, \( m = 16000 \, \text{kg} \)
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