In a rotor, a hollow vertical cylindrical structure rotates about its axis and a person rests against the inner wall. At a particular speed of the rotor, the floor below the person is removed and the person hangs resting against the wall without any floor. If the radius of the rotor is 2m and the coefficient of static friction between the wall and the person is 0.2, find the minimum speed at which the floor may be removed Take `g=10 m/s^2`.

Explanation

To solve the problem, we need to find the minimum speed at which the floor can be removed from the rotor without causing the person to fall. We will use the concepts of circular motion and friction.

### Step-by-Step Solution:

1. **Identify the Forces Acting on the Person:**
- The person experiences two main forces:
- The gravitational force (weight) acting downwards, \( F_g = mg \).
- The frictional force acting upwards, which prevents the person from falling.
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