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A particle is kept fixed on as turntable...

A particle is kept fixed on as turntable rotating uniformly. As seen from the ground the particle goes in a circle,its speed is 20 cm/s and acceleration is 20 cm/s^2 The particle is now shifted to a new positon to make the radius half of the original value. The new values of the speed and acceleration will be

A

`10 cm/s, 10 cm/s^2`

B

`10 cm/s, 80 cm/s^2`

C

`40 cm/s, 10 cm/s^2`

D

`40 cm/s, 40 cm/s^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the speed, acceleration, and radius of the circular motion of the particle on the turntable. ### Step-by-Step Solution: 1. **Identify Given Values:** - Initial speed (v) = 20 cm/s - Initial acceleration (a) = 20 cm/s² - Let the initial radius (r) be R. 2. **Understand the Relationships:** - The speed of a particle in circular motion is given by the formula: \[ v = \omega \cdot r \] where \( \omega \) is the angular velocity (which is constant in this case). - The centripetal acceleration is given by: \[ a = \frac{v^2}{r} = \omega^2 \cdot r \] 3. **Determine the Angular Velocity:** - Since \( v = \omega \cdot r \), we can express \( \omega \) as: \[ \omega = \frac{v}{r} \] - Using the initial conditions, we can substitute \( v = 20 \) cm/s and \( a = 20 \) cm/s² to find \( R \): \[ a = \frac{v^2}{R} \implies 20 = \frac{(20)^2}{R} \implies R = \frac{400}{20} = 20 \text{ cm} \] 4. **New Radius:** - The new radius is half of the original radius: \[ r' = \frac{R}{2} = \frac{20}{2} = 10 \text{ cm} \] 5. **Calculate New Speed:** - Since the angular velocity \( \omega \) is constant, the new speed \( v' \) can be calculated as: \[ v' = \omega \cdot r' = \omega \cdot \left(\frac{R}{2}\right) = \frac{v}{2} = \frac{20}{2} = 10 \text{ cm/s} \] 6. **Calculate New Acceleration:** - The new acceleration \( a' \) can be calculated using the formula for centripetal acceleration: \[ a' = \frac{(v')^2}{r'} = \frac{(10)^2}{10} = \frac{100}{10} = 10 \text{ cm/s}^2 \] ### Final Results: - New speed \( v' = 10 \) cm/s - New acceleration \( a' = 10 \) cm/s² ### Summary: The new values of speed and acceleration when the radius is halved are: - Speed = 10 cm/s - Acceleration = 10 cm/s² ---
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