A force `F=(10+0.50x)` acts on a particle in the x direction, where F is in newton and x in meter./find the work done by this force during a displacement form x=0 tox=2.0m

Explanation

To find the work done by the variable force \( F = (10 + 0.50x) \) during the displacement from \( x = 0 \) to \( x = 2.0 \, \text{m} \), we will follow these steps:

### Step 1: Understand the Work Done by a Variable Force
The work done \( W \) by a variable force can be calculated using the integral of the force with respect to displacement. The formula is given by:
\[ W = \int_{x_1}^{x_2} F \, dx \]
where \( F \) is the force and \( x_1 \) and \( x_2 \) are the initial and final positions.
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