A cubical block of ice of mass m and edge L is placed in a large tray of mass M. If the ice melts, how far does the centre of mass of the system ''ice plus tray'' come down?

Explanation

To solve the problem, we need to find out how far the center of mass of the system (ice plus tray) comes down when the ice melts. Let's break this down step by step.

### Step 1: Define the System
We have a cubical block of ice with mass \( m \) and edge length \( L \) placed in a large tray with mass \( M \).

### Step 2: Initial Position of the Center of Mass
Let’s denote the position of the center of mass of the tray as \( x_1 \) and that of the ice as \( x_2 \). The center of mass \( x \) of the system (ice plus tray) can be calculated using the formula:
\[
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