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A bullet of mass m moving at a speed v h...

A bullet of mass m moving at a speed v hits a ball of mass M kept at rest. A small part having mass m ′ breaks from the ball and sticks to the bullet. The remaining ball is found to move at a speed v 1 ​ , in the direction of the bullet. Find the velocity of the bullet after the collision.

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To solve the problem, we will use the principle of conservation of momentum. The momentum before the collision must equal the momentum after the collision since there are no external forces acting on the system. ### Step-by-Step Solution: 1. **Identify Initial Momentum**: The initial momentum of the system is due to the bullet only, as the ball is at rest. \[ \text{Initial Momentum} = m \cdot v ...
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HC VERMA ENGLISH-CENTRE OF MASS, LINEAR MOMENTUM, COLLISION-Exercises
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  7. Two friends A and B (each weighing 40 kg) are sitting on a frictionles...

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  10. A block of mass 2.0 kg is moving on a frictionless horizontal surface ...

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  11. A bullet of mass 20 g travelling horizontally with a speed of 500 m/s ...

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  12. A projectile is fired with a speed u at an angle theta above a horizon...

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  13. A ball falls vertically on an inclined plane of inclination alpha with...

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  14. Solve tehh previous problem if the coefficient of restitution is e. Us...

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  15. A block of mass 180 g is suspended by a massless spring. The spring ex...

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  16. A bullet of mass 25 g is fired horizontally into a ballistic pendulum ...

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  17. A bullet of mass 20 g moving horizontally at a speed of 300 m/s is fir...

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  18. Two masses m1 and m2 re connected by a spring of spring constant k and...

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  19. Two blocks of masses m1 and m2 are connected by a spring of spring con...

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  20. Cionsider the situation of the previous problem. Suppose each of tbe b...

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