Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is `pi^2ms^-2`.

Explanation

To calculate the time period of a simple pendulum of length 1 meter with an acceleration due to gravity of \( g = \pi^2 \, \text{m/s}^2 \), we can use the formula for the time period \( T \) of a simple pendulum:

\[ T = 2\pi \sqrt{\frac{l}{g}} \]

where:
- \( T \) is the time period,
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