Is it necessary to have two waves of equal intensity to study interfrence pattern? Will there be an effect on clarity if the waves have unequal intensity?

It is found that what waves of same intensity from two coherent sources superpose at a certain point, then the resultant intensity is equal to the intensity of one wave only. This means that the phase difference between the two waves at that point is

The dimensions of intensity of wave are

Consider an YDSE that has different slit width. As a result, amplitude of waves from two slits are A and 2A, respectively. If I_(0) be the maximum intensity of the interference pattern, then intensity of the pattern at a point where phase difference between waves is phi is

Two coherent sources produce waves of different intensities which interfere. A fter interference, the ratio of the maximum intensity to the minimum intensity is 16. The intensity of the waves are in the ratio :

Assertion: Three waves of equal amplitudes interfere at a point. Phase difference between two successive waves is pi/2 . Then, resultant intensity is same as the intensity due to individual wave. Reason: Two different light sources are never coherent.

The ratio of intensities of two waves is 9:16. If these two waves interfere, then determine the ration of the maximum and minimum possible intensities.

The ratio of the intensities of two interfering waves is 81:1. What is the ratio of the maximum to minimum intensity?

Assertion Two coherent sources transmit waves of equal intensity I_(0) Resultant intensity at a point where path difference is lambda/3 is also I_(0) . Reason In interference resultant intensity at any point is the average intensity of two individual intensities.

When interference is produced by two progressive waves of equal frequencies, then the maximum intensity of the resulting sound are N times the intensity of each of the component waves. The value of N is

Two sound waves of equal intensity l, generates beats. The intensity of sound l_(s) produced in beats will be