A piece of ice of mass of `100g` and at temperature `0^(@)C` is put in `200g` of water of `25^(@)` How much ice will melt as the temperature of the water reaches `0^(@)C`? The specific heat capacity of water`= 4200 J kg ^(-1)K^(-1)` and the latent heat of ice `= 3.36 xx 10^(5)J kg^(-1)`

Explanation

To solve the problem, we will use the principle of conservation of energy, which states that the heat lost by the water will be equal to the heat gained by the ice.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Mass of ice, \( m_{\text{ice}} = 100 \, \text{g} = 0.1 \, \text{kg} \)
- Mass of water, \( m_{\text{water}} = 200 \, \text{g} = 0.2 \, \text{kg} \)
- Initial temperature of water, \( T_{\text{initial, water}} = 25^\circ C \)
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