Four `2 cmxx2 cmxx 2cm` cubes of ice are taken from a refrigerator and put in `200ml` of a drink at `10^(@)C`
(a) Find the temperature of the drink when thermal equilibrium is attained in it.
(b) If the ice cubes do not melt completely, find the amount melted.
Assume that no heat is lost to the outside of the drink and that the container has negligible heat capacity. Density of ice `= 900 kg m^(-3)` , density of the drink `= 1000kgm^(-3)`, specific heat capacity of the drink ` = 4200 J kg^(-1)K^(-1)` ,latent heat of fusion of ice `= 3.4 xx 10^(5)Jkg^(-1)`

Answer

B, C

Explanation

Here , Velume of ice ` = 2 xx 2xx 2 = 8 cm^(3)`
Total mass of ice` = 8 xx 0.9 xx 4 = 28.8g`
`:. ` Density of ice `= 0.9gm//cm^(3)`
ice
`mass = 28.8 g temp = 0^(@)C`
Drink
`mass = 200g , temp = 10^(@)C`
Heat required for melting
`= 28.8 xx 80 = 2304 cal
Heat required to drop to `0^(@)C`
` = 200 xx 10 xx 1`
` = 2000 cal`
Hence `2000 cal` releaced by drink must Have been utillised for melting of ice
So , amount of ice is melted bence the temp of the system remain at`0^(@)C`