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Calculate the time required to heat 20kg...

Calculate the time required to heat `20kg` of water from `10^(@)C to 35^(@)C ` using an immersion heater `1000W` Assume that `80%` of the power input is used to heat the water. Specific heat capacity of water `= 4200J kg^(-1)K^(-1)`

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To calculate the time required to heat 20 kg of water from 10°C to 35°C using a 1000W immersion heater, we can follow these steps: ### Step 1: Calculate the heat required to raise the temperature of the water. The formula to calculate the heat required (Q) is given by: \[ Q = m \cdot c \cdot \Delta T \] where: - \( m \) = mass of water = 20 kg - \( c \) = specific heat capacity of water = 4200 J/(kg·K) - \( \Delta T \) = change in temperature = final temperature - initial temperature = \( 35°C - 10°C = 25°C \) Substituting the values: \[ Q = 20 \, \text{kg} \cdot 4200 \, \text{J/(kg·K)} \cdot 25 \, \text{K} \] Calculating this: \[ Q = 20 \cdot 4200 \cdot 25 = 21 \times 10^5 \, \text{J} \] ### Step 2: Determine the effective power of the heater. Since only 80% of the power input is used to heat the water, we need to calculate the effective power (P_eff): \[ P_{\text{eff}} = P \cdot \text{Efficiency} \] where: - \( P \) = power of the heater = 1000 W - Efficiency = 80% = 0.8 Substituting the values: \[ P_{\text{eff}} = 1000 \, \text{W} \cdot 0.8 = 800 \, \text{W} \] ### Step 3: Relate the heat required to the power and time. The energy provided by the heater over time (T) is given by: \[ Q = P_{\text{eff}} \cdot T \] Rearranging this gives: \[ T = \frac{Q}{P_{\text{eff}}} \] Substituting the values: \[ T = \frac{21 \times 10^5 \, \text{J}}{800 \, \text{W}} \] Calculating this: \[ T = \frac{21 \times 10^5}{800} = 2625 \, \text{s} \] ### Step 4: Convert time from seconds to minutes. To convert seconds to minutes, we divide by 60: \[ T_{\text{minutes}} = \frac{2625 \, \text{s}}{60} \approx 43.75 \, \text{minutes} \] Rounding this gives approximately: \[ T \approx 44 \, \text{minutes} \] ### Final Answer: The time required to heat 20 kg of water from 10°C to 35°C using a 1000W immersion heater is approximately **44 minutes**. ---

To calculate the time required to heat 20 kg of water from 10°C to 35°C using a 1000W immersion heater, we can follow these steps: ### Step 1: Calculate the heat required to raise the temperature of the water. The formula to calculate the heat required (Q) is given by: \[ Q = m \cdot c \cdot \Delta T \] where: - \( m \) = mass of water = 20 kg - \( c \) = specific heat capacity of water = 4200 J/(kg·K) ...
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