An electric heater emits 1000W of thermal radiation. The coil has a surface area of `0.02m^(2)` . Assuming that the coil radiates like a blackbody, Find its temperature. `sigma=6.0xx10^(-8)Wm^(-2)K^(-2)` .

Explanation

To find the temperature of the electric heater that emits 1000W of thermal radiation, we can use the Stefan-Boltzmann law, which states that the power emitted by a black body is given by:

\[ P = \sigma A T^4 \]

Where:
- \( P \) is the power emitted (in watts),
- \( \sigma \) is the Stefan-Boltzmann constant (\( 6.0 \times 10^{-8} \, \text{W/m}^2\text{K}^4 \)),
- \( A \) is the surface area (in square meters),
...