A square frame of edge 10 cm is placed with its positive normal making on angle of `60^0` with a uniform electric field of `20 V m^(-1)`. Find the flux of the electric field through the surface bounded by the frame.

Explanation

To find the electric flux through the square frame placed in a uniform electric field, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Edge length of the square frame, \( a = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Electric field strength, \( E = 20 \, \text{V/m} \)
- Angle between the normal to the surface and the electric field, \( \theta = 60^\circ \)
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