The electric field in a region is given by `vecE=E_0x/iota veci`. Find the charge contained inside a cubical volume bounded by the curfaced `x=0, x=alpha, y=0, y=alpha, z=0 and z= alpha`. Take `E_0= 5 xx 10^3 N C^(-1)`, `iota= 2cm and alpha=1 cm`.

Explanation

To find the charge contained inside the cubical volume bounded by the surfaces \( x = 0 \), \( x = \alpha \), \( y = 0 \), \( y = \alpha \), \( z = 0 \), and \( z = \alpha \), we will use Gauss's law, which states:

\[ \Phi_E = \frac{Q_{in}}{\epsilon_0} \]

where \( \Phi_E \) is the electric flux through a closed surface, \( Q_{in} \) is the charge enclosed within that surface, and \( \epsilon_0 \) is the permittivity of free space.

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