A charged partical having a charge of `-2.0 xx 10^(-6) C` is placed close to a nonconducting plate having a surface charge density `4.0 xx 10^(-6) C m^(-2). Fine the force of attraction between the particle and the plate.

Explanation

To find the force of attraction between a charged particle and a non-conducting plate with a given surface charge density, we can follow these steps:

### Step 1: Identify the Given Values
- Charge of the particle, \( q = -2.0 \times 10^{-6} \, \text{C} \)
- Surface charge density of the plate, \( \sigma = 4.0 \times 10^{-6} \, \text{C/m}^2 \)

### Step 2: Calculate the Electric Field (E) due to the Plate
For an infinite non-conducting sheet with surface charge density \( \sigma \), the electric field \( E \) produced is given by the formula:
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