What length of a copper wire of cross-sectional area `0.01 mm^2` will be needed to prepare a resistance of `1 kOmega`? Resistivity of copper `= 1.7 xx 10^(-8) Omega m`.

Explanation

To find the length of a copper wire needed to prepare a resistance of 1 kΩ (1000 Ω) with a given cross-sectional area and resistivity, we can use the formula for resistance:

\[ R = \frac{\rho L}{A} \]

where:
- \( R \) is the resistance,
- \( \rho \) is the resistivity,
- \( L \) is the length of the wire,
...