Home
Class 12
PHYSICS
The constants a and b for the pair silve...

The constants `a and b` for the pair silver-lead are `2.50 muV^@ C^(-1) and 0.012mu V^@ C^(-2)` respectively. For a silver-lead thermocouple with colder junction at `0^@ C`,

A

there will be no neutral temperature

B

there will be no inversion temperature

C

there will not be any thermo-emf even if the junctions are kept at different temperatures

D

there will be no current in the thermocouple even if the junctions are kept at different temperature.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the silver-lead thermocouple with the given constants, we will follow these steps: ### Step 1: Understand the Constants The constants for the silver-lead thermocouple are given as: - \( a = 2.50 \, \mu V/°C \) - \( b = 0.012 \, \mu V/°C^2 \) ### Step 2: Determine the Neutral Temperature The neutral temperature (\( T_n \)) can be calculated using the formula: \[ T_n = -\frac{a}{b} \] Substituting the values of \( a \) and \( b \): \[ T_n = -\frac{2.50 \, \mu V/°C}{0.012 \, \mu V/°C^2} = -208.33 °C \] ### Step 3: Analyze the Result Since the neutral temperature is negative, it indicates that the hot junction temperature would be less than the cold junction temperature when the colder junction is at \( 0 °C \). This situation is not feasible as it contradicts the basic principle of thermocouples, where the hot junction must be at a higher temperature than the cold junction. ### Step 4: Determine the Inversion Temperature The inversion temperature (\( \theta_I \)) is given by: \[ \theta_I = -\frac{2a}{b} \] Substituting the values: \[ \theta_I = -\frac{2 \times 2.50 \, \mu V/°C}{0.012 \, \mu V/°C^2} = -416.67 °C \] Again, this is negative, indicating that there is no inversion temperature in this case. ### Step 5: Evaluate the Options 1. **Option A**: There will be no neutral temperature. (Correct) 2. **Option B**: There will be no inversion temperature. (Correct) 3. **Option C**: There will not be any thermo-emf even if the junctions are kept at different temperatures. (Incorrect) 4. **Option D**: There will be no current in the thermocouple even if the junctions are kept at different temperatures. (Incorrect) ### Conclusion The correct options are A and B. ---
Promotional Banner

Topper's Solved these Questions

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA ENGLISH|Exercise Exercise|24 Videos
  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA ENGLISH|Exercise Short Question|9 Videos
  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA ENGLISH|Exercise Objective 1|6 Videos
  • THE SPECIAL THEORY OF RELATIVITY

    HC VERMA ENGLISH|Exercise Short answer|2 Videos
  • X-Rays

    HC VERMA ENGLISH|Exercise Ques for Short Ans|10 Videos

Similar Questions

Explore conceptually related problems

Three capacitors C_(1),C_(2) and C_(3) are connected as shown in, The potentials of P,Q , and R are V_(1),V_(2), and V_(3) , respectively. Find the potential V_(0) at the function O . .

The standard electrode potential of four metallic elements (A, B, C and D) are + 0.80, –0.76, + 0.12 and +0.34 V respectively. Arrange them in order of decreasing electropositive character

A ,B and C are the points (2, 0),(5,0) and (5,3) respectively. Find coordinates of D such that ABCD is a square.

The EMF generated across a thermocouple with cold junction at 0^(@)C , is E=a theta+btheta^(2) with a =30muV(.^(@)C)^(-1) and b=0.08muV(.^(@)C)^(-2) At E=6mV. The hot junction temperature is about

The standard E_(red)^(@) Values if A, B and C are + 0.68V , - 0.76V , -0.50V respectively. The order of their reducing power is :

The cold junction of a thermocouple is at 0^(@)C . The thermo e.m.f. epsilon , in volts, generated in this thermocouple varies with temperature t^(@)C of the hot junction as epsilon=6+4t-(t^(2))/(32) . The neutral temperature of the thermocouple

The temperatures of the junctions of a bismuth-silver thermocouple are maintained at 0^@ C and 0.001^@ C . Find the thermo-emf (Seebeck emf) developed. For bismuth-silver, a = - 46 xx 10^(-6) V^@ C^(-1) and b= -0.48 xx 10^(-6) V^@ V^@ C^(-2) .

For a copper-iron and a chromel-alumel thermocouple, the plots between thermoelectric emf and the temperature theta of the hot junction (when the cold junction is at 0^(@)C )are found to satisfy approximately the parabola equation V=alpha theta+(1)/(2)betatheta^(2) with alpha=14muV^(@)C^(-1) beta=-0.04V^(@)C^(-2) (copper-iron) alpha=41muCV^(@)C^(-1),beta=-0.002V^(@)C^(-2) (chromel-alumel) Which of the two thermocouples would you use to measure temperature in the range of a about 500^(@)C to 600^(@)C ?

If the vertices A,B,C of a triangle ABC are (1,2,3),(-1,0,0) ,(0,1,2) , respectively, then find angleABC .