Consider the circuit shown in the fig. sliding contact is being pulled towards right so that the resistance in the circuit is increasing. Its valve at the instant shown in `12 Omega`. Will the current be more then 0.50 A or less than it at this instant?

Explanation

As the sliding contact is being pulled, the current in the circuit changes
An induced emf`varepsilon =- L(di)/(dt) is produced across the inductor
The net emf in the circuit is `6 V - L (di)/(dt)` and hence the current is ` i= (6 V - L(di)/(dt))/(12 Omega) at the instant shown
now the resistance in the circuit is increasing, the current is decreasing and `so(di)/(dt)` is nagative thus, the numerator of (i) is more then 6 V and hence i is greater then `(6 V)/ (12 Omega) =0
50 A .