An LR circuit having `L = 4.0 H, R = 1.0 Omega and epsilon = 6.0 V` is switched on at `t = 0`. find the power dissipated in joule heating at `t = 4.0 s`.

Explanation

To solve the problem step by step, we will follow the process of calculating the current in the LR circuit and then using that current to find the power dissipated due to Joule heating.

### Step 1: Identify the parameters of the LR circuit
Given:
- Inductance \( L = 4.0 \, \text{H} \)
- Resistance \( R = 1.0 \, \Omega \)
- Voltage \( \epsilon = 6.0 \, \text{V} \)
- Time \( t = 4.0 \, \text{s} \)
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