A coil of resistance `40 Omega` is connected across a 4.0 V battery. 0.10 s after the battery is connected, the current in the coil is 63 mA. Find the inductance of the coil.

Explanation

To find the inductance of the coil, we will use the formula for current in an inductor connected to a DC voltage source. The formula is given by:

\[ I(t) = I_0 \left(1 - e^{-\frac{t}{\tau}}\right) \]

where:
- \( I(t) \) is the current at time \( t \),
- \( I_0 \) is the maximum current (steady-state current),
- \( \tau \) is the time constant given by \( \tau = \frac{L}{R} \),
...