An inductor coil of inductance 17 mH is constructed from a copper wire of length 100 m and cross - sectional are `1mm^2`. Calculate the time constant of the circuit if this inductor is joined across an ideal battery. The resistivity of copper =`1.7 X 10^(-8) Omega m.

Explanation

To solve the problem, we need to calculate the time constant (τ) of the circuit when an inductor is connected across an ideal battery. The time constant is given by the formula:

\[ \tau = \frac{L}{R} \]

where \(L\) is the inductance and \(R\) is the resistance of the wire used to create the inductor.

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