A series AC circuit contains an inductor `(20 mH)`, a capacitor `(100 muF)`, a resistor `(50 Omega)` and an AC source of `12 V, 50 Hz`. Find the energy dissipated in the circuit in `1000 s`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the given values
- Inductance, \( L = 20 \, \text{mH} = 20 \times 10^{-3} \, \text{H} \)
- Capacitance, \( C = 100 \, \mu\text{F} = 100 \times 10^{-6} \, \text{F} \)
- Resistance, \( R = 50 \, \Omega \)
- RMS Voltage, \( V_{\text{RMS}} = 12 \, \text{V} \)
- Frequency, \( f = 50 \, \text{Hz} \)
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