A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%, C=12%, O=48%` If the law of constant proportions is true. Then the weight of calcium in `4 g` of a sample of calcium carbonate obtained from another source will be

Options

A. `0.016 g`
B. `0.16 g`
C. `1.6 g`
D. `16 g`

Answer

To solve the problem, we need to determine the weight of calcium in a 4 g sample of calcium carbonate (CaCO₃) based on its percentage composition.

### Step-by-Step Solution:

1. **Understand the Percentage Composition**:
The problem states that in calcium carbonate (CaCO₃), the percentage composition is as follows:
- Calcium (Ca) = 40%
- Carbon (C) = 12%
- Oxygen (O) = 48%

2. **Identify the Total Weight of the Sample**:
We are given a sample weight of 4 g of calcium carbonate.

3. **Calculate the Weight of Calcium in the Sample**:
To find the weight of calcium in the 4 g sample, we can use the percentage of calcium in the compound:
\[ \text{Weight of Calcium} = \left( \frac{\text{Percentage of Calcium}}{100} \right) \times \text{Total Weight of Sample} \]
Substituting the values:
\[ \text{Weight of Calcium} = \left( \frac{40}{100} \right) \times 4 \text{ g} \]

4. **Perform the Calculation**:
\[ \text{Weight of Calcium} = 0.4 \times 4 \text{ g} = 1.6 \text{ g} \]

5. **Conclusion**:
Therefore, the weight of calcium in the 4 g sample of calcium carbonate is **1.6 g**.

### Final Answer:
The weight of calcium in 4 g of calcium carbonate is **1.6 g**.

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