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Two elemets X( atomic weight =75) and Y(...

Two elemets `X(` atomic weight `=75)` and `Y(` atomic weight `=16)` combine to give a compound having `75.8%` X.` The formula of the compound is

A

XY

B

`X_(2)Y`

C

`X_(2)Y_(2)`

D

`X_(2)Y_(3)`

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The correct Answer is:
To find the formula of the compound formed by elements X and Y, we can follow these steps: ### Step 1: Identify the given data - Atomic weight of element X = 75 - Atomic weight of element Y = 16 - Percentage of element X in the compound = 75.8% ### Step 2: Calculate the percentage of element Y To find the percentage of element Y, we subtract the percentage of element X from 100%: \[ \text{Percentage of Y} = 100\% - 75.8\% = 24.2\% \] ### Step 3: Set up the ratio of the elements We will now find the ratio of the number of moles of each element in the compound using their percentages and atomic weights. \[ \text{Moles of X} = \frac{\text{Percentage of X}}{\text{Atomic weight of X}} = \frac{75.8}{75} \] \[ \text{Moles of Y} = \frac{\text{Percentage of Y}}{\text{Atomic weight of Y}} = \frac{24.2}{16} \] ### Step 4: Calculate the moles Calculating the moles for each element: \[ \text{Moles of X} = \frac{75.8}{75} \approx 1.01 \] \[ \text{Moles of Y} = \frac{24.2}{16} \approx 1.51 \] ### Step 5: Find the simplest whole number ratio To find the simplest whole number ratio, we divide both values by the smallest value obtained: \[ \text{Ratio of X} = \frac{1.01}{1.01} \approx 1 \] \[ \text{Ratio of Y} = \frac{1.51}{1.01} \approx 1.49 \approx 1.5 \] ### Step 6: Convert to whole numbers To convert the ratio into whole numbers, we can multiply both values by 2 to eliminate the fraction: \[ \text{X} = 1 \times 2 = 2 \] \[ \text{Y} = 1.5 \times 2 = 3 \] ### Step 7: Write the empirical formula From the whole number ratio, we can write the empirical formula of the compound as: \[ \text{Formula} = X_2Y_3 \] ### Final Answer The formula of the compound is \( X_2Y_3 \). ---
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