A sample of peanut oil weighing 2g is ad...

A sample of peanut oil weighing 2g is added to `25mL` of `0.40M KOH`. After saponification is complete, `8.5mL` of `0.28M H_2SO_4` is needed to nuetralize excess of `KOH`. The saponification number of peanut oil is : (saponification number is defined as the milligrams of `KOH` consumed by 1g of oil)

A

146.72

B

223.44

C

98.44

D

98.9

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A

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