Balance the following equation and choose the quantity which is the sum of the coefficients of and products:
`.....CS_(2)+ .....Cl_(2) to ......C Cl_(4) + ....S_(2)Cl_(2)`

Options

A. 5
B. 3
C. 6
D. 2

Answer

To balance the chemical equation and find the sum of the coefficients of the products, follow these steps:

### Step 1: Write the unbalanced equation
The unbalanced equation is:
\[ \text{CS}_2 + \text{Cl}_2 \rightarrow \text{CCl}_4 + \text{S}_2\text{Cl}_2 \]

### Step 2: Count the number of atoms of each element on both sides
- **Reactants:**
- Carbon (C): 1 (from CS₂)
- Sulfur (S): 2 (from CS₂)
- Chlorine (Cl): 2 (from Cl₂)

- **Products:**
- Carbon (C): 1 (from CCl₄)
- Sulfur (S): 2 (from S₂Cl₂)
- Chlorine (Cl): 4 (from CCl₄) + 2 (from S₂Cl₂) = 6

### Step 3: Balance the equation
- The carbon and sulfur are already balanced (1 C and 2 S on both sides).
- The chlorine is not balanced (2 on the left, 6 on the right). To balance chlorine, we can adjust the coefficient of Cl₂.

To balance the chlorine:
- We need 6 Cl on the left side, so we multiply Cl₂ by 3:
\[ \text{CS}_2 + 3\text{Cl}_2 \rightarrow \text{CCl}_4 + \text{S}_2\text{Cl}_2 \]

### Step 4: Check the balance again
- **Reactants:**
- C: 1
- S: 2
- Cl: 3 × 2 = 6

- **Products:**
- C: 1
- S: 2
- Cl: 4 (from CCl₄) + 2 (from S₂Cl₂) = 6

Now, the equation is balanced:
\[ \text{CS}_2 + 3\text{Cl}_2 \rightarrow \text{CCl}_4 + \text{S}_2\text{Cl}_2 \]

### Step 5: Identify the coefficients of the products
The coefficients of the products (CCl₄ and S₂Cl₂) are both 1:
- CCl₄: 1
- S₂Cl₂: 1

### Step 6: Calculate the sum of the coefficients of the products
Sum = 1 (for CCl₄) + 1 (for S₂Cl₂) = 2

### Final Answer
The sum of the coefficients of the products is **2**.

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