Balance the followings equations and choose the quantity which is the sum of the coefficients of reactants and products : `........PtCI_4+.....XeF_2 - gt Pt F_6+......CIF+.....Xe`

Options

A. (a) 16
B. (b) 13
C. (c) 18
D. (d) 12

Answer

To balance the equation \( \text{PtCl}_4 + \text{XeF}_2 \rightarrow \text{PtF}_6 + \text{ClF} + \text{Xe} \) and find the sum of the coefficients of the reactants and products, we will follow these steps:

### Step 1: Write the unbalanced equation
The unbalanced equation is:
\[ \text{PtCl}_4 + \text{XeF}_2 \rightarrow \text{PtF}_6 + \text{ClF} + \text{Xe} \]

### Step 2: Count the number of each type of atom on both sides
- **Reactants:**
- Pt: 1 (from PtCl4)
- Cl: 4 (from PtCl4)
- Xe: 1 (from XeF2)
- F: 2 (from XeF2)

- **Products:**
- Pt: 1 (from PtF6)
- Cl: 1 (from ClF)
- Xe: 1 (from Xe)
- F: 6 (from PtF6) + 1 (from ClF) = 7

### Step 3: Balance the chlorine (Cl) atoms
Currently, we have 4 Cl on the reactant side and only 1 on the product side. To balance Cl, we multiply ClF by 4:
\[ \text{PtCl}_4 + \text{XeF}_2 \rightarrow \text{PtF}_6 + 4\text{ClF} + \text{Xe} \]

### Step 4: Count the atoms again
- **Reactants:**
- Pt: 1
- Cl: 4
- Xe: 1
- F: 2

- **Products:**
- Pt: 1
- Cl: 4 (from 4 ClF)
- Xe: 1
- F: 6 (from PtF6) + 4 (from 4 ClF) = 10

### Step 5: Balance the fluorine (F) atoms
Now we have 2 F on the reactant side and 10 on the product side. To balance F, we multiply XeF2 by 5:
\[ \text{PtCl}_4 + 5\text{XeF}_2 \rightarrow \text{PtF}_6 + 4\text{ClF} + \text{Xe} \]

### Step 6: Count the atoms again
- **Reactants:**
- Pt: 1
- Cl: 4
- Xe: 5 (from 5 XeF2)
- F: 10 (from 5 XeF2)

- **Products:**
- Pt: 1
- Cl: 4 (from 4 ClF)
- Xe: 1
- F: 6 (from PtF6) + 4 (from 4 ClF) = 10

### Step 7: Balance the xenon (Xe) atoms
We have 5 Xe on the reactant side and 1 on the product side. To balance Xe, we multiply Xe by 5:
\[ \text{PtCl}_4 + 5\text{XeF}_2 \rightarrow \text{PtF}_6 + 4\text{ClF} + 5\text{Xe} \]

### Step 8: Final count of atoms
- **Reactants:**
- Pt: 1
- Cl: 4
- Xe: 5
- F: 10

- **Products:**
- Pt: 1
- Cl: 4
- Xe: 5
- F: 10

### Step 9: Write the coefficients
- Coefficients of reactants:
- PtCl4: 1
- XeF2: 5
- Coefficients of products:
- PtF6: 1
- ClF: 4
- Xe: 5

### Step 10: Calculate the sum of coefficients
Sum of coefficients = \( 1 + 5 + 1 + 4 + 5 = 16 \)

### Final Answer
The sum of the coefficients of the reactants and products is **16**.

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