What will be the normally of a solution obtained by mixiing 0.45N and 0.60N NaOH in the ratio 2:1 by volume?

Options

A. 0.4N
B. 0.5N
C. 1.05N
D. 0.15N

Answer

To find the normality of a solution obtained by mixing 0.45N and 0.60N NaOH in the ratio of 2:1 by volume, we can follow these steps:

### Step 1: Define the volumes used for mixing
Let’s assume we take 2 volumes of the 0.45N NaOH solution and 1 volume of the 0.60N NaOH solution. We can denote these volumes as:
- Volume of 0.45N NaOH = 2V
- Volume of 0.60N NaOH = V

### Step 2: Calculate the total volume of the mixed solution
The total volume of the mixed solution can be calculated as:
\[ \text{Total Volume} = 2V + V = 3V \]

### Step 3: Calculate the equivalent normality contributions from each solution
The normality contribution from each solution can be calculated as follows:
- For the 0.45N NaOH solution:
\[ \text{Normality Contribution} = 0.45N \times 2V = 0.90N \cdot V \]

- For the 0.60N NaOH solution:
\[ \text{Normality Contribution} = 0.60N \times V = 0.60N \cdot V \]

### Step 4: Add the normality contributions
Now, we can add the normality contributions from both solutions:
\[ \text{Total Normality Contribution} = 0.90N \cdot V + 0.60N \cdot V = (0.90 + 0.60)N \cdot V = 1.50N \cdot V \]

### Step 5: Calculate the normality of the mixed solution
To find the normality of the mixed solution, we divide the total normality contribution by the total volume:
\[ \text{Normality of Mixed Solution} = \frac{1.50N \cdot V}{3V} \]

### Step 6: Simplify the expression
The volume \( V \) cancels out:
\[ \text{Normality of Mixed Solution} = \frac{1.50N}{3} = 0.50N \]

### Final Answer
The normality of the solution obtained by mixing 0.45N and 0.60N NaOH in the ratio 2:1 is **0.50N**.

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