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1.25g of a solid dibasic acid is complet...

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar `Ba(OH_(2))` solution. Molecular mass of the acid is:

A

100

B

150

C

120

D

200

Text Solution

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The correct Answer is:
To find the molecular mass of the dibasic acid that is completely neutralized by barium hydroxide, we can follow these steps: ### Step 1: Determine the number of equivalents of barium hydroxide (Ba(OH)₂) The number of equivalents can be calculated using the formula: \[ \text{Number of equivalents} = \text{Molarity} \times \text{Volume in liters} \times n \] For barium hydroxide, \( n = 2 \) (since it can donate 2 hydroxide ions). Given: - Molarity of Ba(OH)₂ = 0.25 M - Volume = 25 mL = 0.025 L Calculating the number of equivalents: \[ \text{Number of equivalents of Ba(OH)₂} = 0.25 \, \text{mol/L} \times 0.025 \, \text{L} \times 2 = 0.0125 \, \text{equivalents} \] ### Step 2: Determine the number of equivalents of the dibasic acid (H₂A) Since the dibasic acid is completely neutralized by barium hydroxide, the number of equivalents of the acid will be equal to the number of equivalents of barium hydroxide: \[ \text{Number of equivalents of H₂A} = 0.0125 \, \text{equivalents} \] ### Step 3: Calculate the number of moles of the dibasic acid (H₂A) The number of equivalents is also related to the number of moles by the formula: \[ \text{Number of equivalents} = \text{Number of moles} \times n \] For the dibasic acid, \( n = 2 \). Rearranging the formula to find the number of moles: \[ \text{Number of moles of H₂A} = \frac{\text{Number of equivalents}}{n} = \frac{0.0125}{2} = 0.00625 \, \text{moles} \] ### Step 4: Calculate the molecular mass of the dibasic acid Using the formula: \[ \text{Number of moles} = \frac{\text{Weight}}{\text{Molecular mass}} \] Rearranging to find the molecular mass: \[ \text{Molecular mass} = \frac{\text{Weight}}{\text{Number of moles}} \] Given that the weight of the acid is 1.25 g: \[ \text{Molecular mass} = \frac{1.25 \, \text{g}}{0.00625 \, \text{moles}} = 200 \, \text{g/mol} \] ### Conclusion The molecular mass of the dibasic acid is **200 g/mol**. ---
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