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10L of hard water required 5.6g of lime ...

10L of hard water required 5.6g of lime for removing hardness. Hence temperorary hardness in ppm of `CaCO_(3)` is:

A

1000

B

2000

C

100

D

1

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The correct Answer is:
To determine the temporary hardness of hard water in ppm of calcium carbonate (CaCO₃), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - Volume of hard water = 10 L - Mass of lime (CaO) required = 5.6 g 2. **Convert Volume of Hard Water to Milliliters**: - Since 1 L = 1000 mL, - Therefore, 10 L = 10 × 1000 mL = 10,000 mL. 3. **Determine the Molar Mass of Calcium Oxide (CaO)**: - Molar mass of CaO = 40 (Ca) + 16 (O) = 56 g/mol. 4. **Calculate the Number of Moles of Calcium Oxide**: - Number of moles of CaO = Mass / Molar mass = 5.6 g / 56 g/mol = 0.1 mol. 5. **Determine the Reaction with Calcium Bicarbonate**: - The reaction of CaO with calcium bicarbonate (Ca(HCO₃)₂) produces calcium carbonate (CaCO₃). - The stoichiometry of the reaction indicates that 1 mole of CaO will produce 1 mole of CaCO₃. 6. **Calculate the Moles of Calcium Carbonate Produced**: - Therefore, moles of CaCO₃ produced = moles of CaO = 0.1 mol. 7. **Calculate the Mass of Calcium Carbonate Produced**: - Molar mass of CaCO₃ = 40 (Ca) + 12 (C) + 48 (O₃) = 100 g/mol. - Mass of CaCO₃ = Number of moles × Molar mass = 0.1 mol × 100 g/mol = 10 g. 8. **Determine the Mass of CaCO₃ in 1 mL of Hard Water**: - Since 10 g of CaCO₃ is produced in 10,000 mL of hard water, - Mass of CaCO₃ per mL = 10 g / 10,000 mL = 0.001 g/mL. 9. **Calculate the Mass of CaCO₃ in 1,000,000 mL (1,000 L)**: - To find the mass in 1,000,000 mL (which is 1,000 L), we multiply the mass per mL by 1,000,000 mL: - Mass of CaCO₃ in 1,000,000 mL = 0.001 g/mL × 1,000,000 mL = 1,000 g. 10. **Convert to ppm**: - Since ppm (parts per million) is equivalent to mg/L, and we have 1,000 g in 1,000 L, we can express this as: - 1,000 g = 1,000,000 mg. - Therefore, the temporary hardness in ppm of CaCO₃ = 1,000,000 mg / 1,000 L = 1,000 ppm. ### Final Answer: The temporary hardness of the hard water in ppm of CaCO₃ is **1,000 ppm**. ---
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