Which of the following statements regarding the compound `A_(x)B_(y)` is /are correct?

Options

A. 1 mole of `A_(x)B_(y)` contains 1 mole of A and 1 mole B
B. 1 equivalent of `A_(x)B_(y)` contains 1 equivalent of A and 1 equivalent of B
C. 1 mole of `A_(x)B_(y)` contains x moles of A and y moles of B
D. equivalent mass of `A_(x)B_(y)`=equivalent mass of A +equivalent mass of B

Answer

To analyze the statements regarding the compound \( A_xB_y \), we need to evaluate each statement based on stoichiometric principles. Let's break down the solution step by step.

### Step 1: Understand the Composition of the Compound
The compound \( A_xB_y \) consists of \( x \) moles of element \( A \) and \( y \) moles of element \( B \). This means that in one mole of \( A_xB_y \), there are \( x \) moles of \( A \) and \( y \) moles of \( B \).

**Hint:** Identify the components of the compound and their respective quantities.

### Step 2: Evaluate the First Statement
The first statement claims that the equivalent number of equivalents of \( A_x \) and \( B_y \) is equal to the equivalents of \( A_y^- \) and \( B_x^+ \).

To analyze this:
- The equivalents of \( A_x \) and \( B_y \) can be calculated based on their valencies.
- The equivalents of \( A_y^- \) and \( B_x^+ \) should also be calculated similarly.

Since the equivalents are based on the same number of moles and their respective valencies, this statement is **correct**.

**Hint:** Equivalents depend on the valency and the number of moles.

### Step 3: Evaluate the Second Statement
The second statement suggests that one mole of \( A_xB_y \) will produce \( x \) moles of \( A \) and \( y \) moles of \( B \).

This is straightforward:
- From one mole of \( A_xB_y \), you indeed get \( x \) moles of \( A \) and \( y \) moles of \( B \).

Thus, this statement is also **correct**.

**Hint:** Consider the stoichiometry of the decomposition of the compound.

### Step 4: Evaluate the Third Statement
The third statement claims that the equivalent weight of \( A_x \) and \( B_y \) is equal to the sum of the equivalent weights of \( A \) and \( B \).

This can be evaluated as follows:
- The equivalent weight of a compound is defined as the molecular weight divided by the number of equivalents.
- Therefore, the equivalent weight of \( A_xB_y \) is indeed the sum of the equivalent weights of \( A \) and \( B \).

This statement is also **correct**.

**Hint:** Remember that equivalent weight is derived from the molecular weight and the number of equivalents.

### Conclusion
After evaluating all statements, we find that all of them are correct.

### Final Answer
All statements regarding the compound \( A_xB_y \) are correct.