How many minutes are required to deliver `3.21xx10^(6)` coulombs using a current of 500 A used in the commercial production of chlorine?

Options

A. 8.3
B. `5.3xx10^(4)`
C. 6420
D. 107

Answer

To solve the problem of how many minutes are required to deliver \(3.21 \times 10^{6}\) coulombs using a current of 500 A, we can follow these steps:

### Step 1: Understand the relationship between charge, current, and time
The relationship between charge (Q), current (I), and time (t) is given by the formula:
\[ t = \frac{Q}{I} \]
where:
- \(t\) is the time in seconds,
- \(Q\) is the charge in coulombs,
- \(I\) is the current in amperes.

### Step 2: Substitute the values into the formula
Given:
- \(Q = 3.21 \times 10^{6}\) coulombs,
- \(I = 500\) A.

Now, substituting these values into the formula:
\[ t = \frac{3.21 \times 10^{6}}{500} \]

### Step 3: Calculate the time in seconds
Now, perform the calculation:
\[ t = \frac{3.21 \times 10^{6}}{500} = 6420 \text{ seconds} \]

### Step 4: Convert seconds to minutes
To convert seconds to minutes, we use the conversion factor that 1 minute = 60 seconds. Thus:
\[ \text{minutes} = \frac{6420 \text{ seconds}}{60} \]

Calculating this gives:
\[ \text{minutes} = 107 \text{ minutes} \]

### Final Answer
Therefore, the time required to deliver \(3.21 \times 10^{6}\) coulombs using a current of 500 A is **107 minutes**.

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