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An electrolysis of a oxytungsten complex...

An electrolysis of a oxytungsten complex ion using 1.10 A for 40min produces 0.838 g of tungsten. What is the charge on tungsten in the material? (Atomic mass of W=184)

A

6

B

2

C

4

D

1

Text Solution

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The correct Answer is:
To determine the charge on tungsten in the material produced during the electrolysis of the oxytungsten complex ion, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values:** - Current (I) = 1.10 A - Time (T) = 40 minutes - Mass of tungsten produced (W) = 0.838 g - Atomic mass of tungsten (M) = 184 g/mol 2. **Convert Time to Seconds:** \[ T = 40 \text{ minutes} \times 60 \text{ seconds/minute} = 2400 \text{ seconds} \] 3. **Use Faraday's Law of Electrolysis:** The mass of the substance produced during electrolysis can be calculated using the formula: \[ W = \frac{M \cdot I \cdot T}{n \cdot F} \] Where: - \( W \) = mass of tungsten produced (g) - \( M \) = molar mass of tungsten (g/mol) - \( I \) = current (A) - \( T \) = time (s) - \( n \) = number of moles of electrons transferred (charge on tungsten) - \( F \) = Faraday's constant (approximately 96500 C/mol) 4. **Rearrange the Formula to Solve for n:** \[ n = \frac{M \cdot I \cdot T}{W \cdot F} \] 5. **Substitute the Known Values:** \[ n = \frac{184 \text{ g/mol} \cdot 1.10 \text{ A} \cdot 2400 \text{ s}}{0.838 \text{ g} \cdot 96500 \text{ C/mol}} \] 6. **Calculate n:** - First, calculate the numerator: \[ 184 \cdot 1.10 \cdot 2400 = 486240 \] - Then, calculate the denominator: \[ 0.838 \cdot 96500 = 80827 \] - Now, divide the two results: \[ n = \frac{486240}{80827} \approx 6.02 \] 7. **Determine the Charge on Tungsten:** Since the charge must be an integer, we round \( n \) to the nearest whole number: \[ n \approx 6 \] ### Final Answer: The charge on tungsten in the material is \( +6 \). ---
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