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Based on the following informations arra...

Based on the following informations arrange four metals, A,B,C and D in order of increasing ability to act as reducing agents :
(I) Only C react with 1 M HCl to give `H_(2)`(g)
(II) When A is added to solution of the other metal ions, metallic D is formed but not B or C

A

(a) `DgtAgtCgtB`

B

(b) `AgtDgtCgtB`

C

(c) `BgtDgtAgtC`

D

(d) `DgtAgtBgtC`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of increasing ability to act as reducing agents for the metals A, B, C, and D, we will analyze the provided information step by step. ### Step 1: Analyze the first statement The first statement tells us that only metal C reacts with 1 M HCl to produce hydrogen gas (H₂). - **Chemical Reaction**: C + 2HCl → CCl₂ + H₂ - **Interpretation**: For C to produce H₂, it must be able to reduce the hydrogen ions (H⁺) from HCl to hydrogen gas. This means that C acts as a reducing agent in this reaction. ### Step 2: Determine the reduction potential of C Since C is able to reduce H⁺ to H₂, it implies that the standard reduction potential (E°) for C is less than that of H⁺ (which is 0 V for the reduction of H⁺ to H₂). - **Conclusion**: E° for C < E° for H⁺ (0 V) → E° for C is negative. ### Step 3: Analyze the second statement The second statement indicates that when metal A is added to a solution containing ions of the other metals (B and C), it forms metallic D but does not reduce B or C. - **Interpretation**: This suggests that A can reduce D from its ionic form to its metallic form, indicating that A is a stronger reducing agent than D. Since A does not react with B or C, it implies that A cannot reduce them. ### Step 4: Determine the reduction potentials based on the second statement From the second statement, we can derive the following relationships: - A must have a higher reduction potential than both B and C because it does not reduce them. - A must have a lower reduction potential than D because it can reduce D. Thus, we can summarize: - E° for A > E° for B - E° for A > E° for C - E° for A < E° for D ### Step 5: Arrange the metals based on their reducing abilities Based on the information gathered: 1. C has the lowest reduction potential (most negative) and is the weakest reducing agent. 2. B is next, as it is not reduced by A. 3. D is next, as A can reduce it. 4. A has the highest reduction potential and is the strongest reducing agent. ### Final Order The order of increasing ability to act as reducing agents is: **C < B < D < A**
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